-56x^2-31+36=0

Solution for -56x^2-31+36=0 equation:

-56x^2-31+36=0

We add all the numbers together, and all the variables

-56x^2+5=0

a = -56; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-56)·5
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*-56}=\frac{0-4\sqrt{70}}{-112}
=-\frac{4\sqrt{70}}{-112}
=-\frac{\sqrt{70}}{-28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*-56}=\frac{0+4\sqrt{70}}{-112}
=\frac{4\sqrt{70}}{-112}
=\frac{\sqrt{70}}{-28}
$